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Properties of operations

Example 1
Frank walks his dog for \latex{\frac{2}{3}} of an \latex{ hour } every morning and \latex{\frac{4}{5}} of an \latex{ hour } every evening. How many \latex{ hours } does he walk the dog in \latex{ 5 } \latex{ days }?
Solution
They walk \latex{\frac{2}{3}+\frac{4}{5}} \latex{ hours } a \latex{ day. }
In 5 \latex{ days }: \latex{5\times \left(\frac{2}{3}+\frac{4}{5} \right)=5\times \left(\frac{10}{15}+\frac{12}{15} \right)=\overset{1}{\cancel{5}}\times \frac{22}{\underset{3}{\cancel{15}} }=\frac{22}{3}=7\frac{1}{3}} .
Calculating in another way: in \latex{ 5 } \latex{ days }, they walk \latex{5\times \frac{2}{3}} \latex{ hours } in the mornings and \latex{5\times \frac{4}{5}} \latex{ hours } in the evenings.
\latex{5\times \dfrac{2}{3}+\overset{1}{\cancel{5}}\times \dfrac{4}{\underset{1}{\cancel{5}} }=\dfrac{10}{3}+4=3\dfrac{1}{3}+4=7\dfrac{1}{3}.}
In \latex{ 5 } \latex{ days }, Frank spends \latex{7\frac{1}{3}} \latex{ hours } walking his dog.
In the case of fractions, apply what you have learned about the order of operations.
- First, perform the operations between brackets.
- Perform the multiplications and divisions from left to right.
- Perform the additions and subtractions from left to right.
\latex{\left(\dfrac{3}{2}-\dfrac{5}{4} \right)\times \left(\dfrac{2}{3}-\dfrac{5}{6} \right)=\dfrac{6-5}{4} \times \dfrac{4-5}{6}=\dfrac{1}{4}\times \left(-\dfrac{1}{6} \right)=-\dfrac{1}{24}.}
\latex{\dfrac{1}{4}\times \dfrac{1}{3}\ -\dfrac{1}{6}\times \dfrac{5}{2}=\dfrac{1}{12}-\dfrac{5}{12}=-\dfrac{\overset{1}{\cancel{4}} }{\underset{3}{\cancel{12}} }=-\dfrac{1}{3}.}
\latex{\dfrac{7}{3}-\dfrac{4}{5}\div \dfrac{12}{25}=\dfrac{7}{3}-\dfrac{\overset{1}{\cancel{4}} }{\underset{1}{\cancel{5}} }\times \dfrac{\overset{5}{\cancel{25}} }{\underset{3}{\cancel{12}} }=\dfrac{7}{3}-\dfrac{5}{3}=\dfrac{2}{3}.}
\latex{\dfrac{1}{4}\times \dfrac{1}{3}\ -\dfrac{1}{6}\times \dfrac{5}{2}=\dfrac{1}{12}-\dfrac{5}{12}=-\dfrac{\overset{1}{\cancel{4}} }{\underset{3}{\cancel{12}} }=-\dfrac{1}{3}.}
\latex{\dfrac{7}{3}-\dfrac{4}{5}\div \dfrac{12}{25}=\dfrac{7}{3}-\dfrac{\overset{1}{\cancel{4}} }{\underset{1}{\cancel{5}} }\times \dfrac{\overset{5}{\cancel{25}} }{\underset{3}{\cancel{12}} }=\dfrac{7}{3}-\dfrac{5}{3}=\dfrac{2}{3}.}
The properties of operations are valid for fractions as well.
- The addends are interchangeable.
\latex{\begin{aligned}\begin{rcases}\textcolor{#2AB7EC}{\left(-\dfrac{1}{4} \right)}+\textcolor{#F56060}{\dfrac{2}{5}}=-\dfrac{5}{20}+\dfrac{8}{20}&=\dfrac{3}{20} \\ \textcolor{#f56060}{\dfrac{2}{5}} +\textcolor{#2AB7EC}{\left(-\dfrac{1}{4} \right)}=\dfrac{8}{20}-\dfrac{5}{20}&=\dfrac{3}{20} \end{rcases}\end{aligned} \textcolor{#2AB7EC}{-\dfrac{1}{4}}+\textcolor{#f56060}{\dfrac{2}{5}}=\textcolor{#f56060}{\dfrac{2}{5}}+\textcolor{#2AB7EC}{\left(-\dfrac{1}{4} \right)}}
- The factors of any multiplication are interchangeable.
\latex{\begin{aligned}\begin{rcases}\textcolor{#2ab7ec}{\left(-\dfrac{1}{4} \right)}\times \textcolor{#f65060}{\dfrac{2}{5}}=-\dfrac{1}{\underset{2}{\cancel{4}} }\times \dfrac{\overset{1}{\cancel{2}} }{5}&=-\dfrac{1}{10} \\ \textcolor{#f65060}{\dfrac{2}{5}}\times \textcolor{#2ab7ec}{\left(-\dfrac{1}{4} \right)}=\dfrac{\overset{1}{\cancel{2}}}{5}\times \left(-\dfrac{1}{\underset{2}{\cancel{4}}} \right) &=-\dfrac{1}{10} \end{rcases}\end{aligned} \textcolor{#2ab7ec}{\left(-\dfrac{1}{4} \right)}\times \textcolor{#f65060}{\dfrac{2}{5}}=\textcolor{#f65060}{\dfrac{2}{5}}\times \textcolor{#2ab7ec}{\left(-\dfrac{1}{4} \right)}}
- The addends can be grouped arbitrarily.
\latex{\begin{rcases}\begin{aligned} \textcolor{#2ab7ec}{\left(\dfrac{3}{5}+\dfrac{7}{10} \right)}-\dfrac{1}{2}=\left(\dfrac{6}{10}+\dfrac{7}{10} \right)-\dfrac{5}{10}=\dfrac{13}{10}-\dfrac{5}{10}=\dfrac{8}{10}&=\dfrac{4}{5} \\[10pt] \dfrac{3}{5}+\textcolor{#2ab7ec}{\left(\dfrac{7}{10}-\dfrac{1}{2} \right)}=\dfrac{6}{10}+\left(\dfrac{7}{10}-\dfrac{5}{10} \right)=\dfrac{6}{10}+\dfrac{2}{10}=\dfrac{8}{10}&=\dfrac{4}{5} \\[10pt] \dfrac{3}{5}+\dfrac{7}{10}-\dfrac{1}{2}=\dfrac{6}{10}+\dfrac{7}{10}-\dfrac{5}{10}=\dfrac{8}{10}&=\dfrac{4}{5} \end{aligned}\end{rcases}}
that is
\latex{\textcolor{#2ab7ec}{\left(\frac{3}{5}+\frac{7}{10} \right)}-\frac{1}{2}=\frac{3}{5}+\textcolor{#2ab7ec}{\left(\frac{7}{10}-\frac{1}{2} \right)}=\frac{3}{5}+\frac{7}{10}-\frac{1}{2}}
- The factors can be grouped arbitrarily.
\latex{\begin{rcases}\begin{alinged} \textcolor{#2ab7ec}{\left(\dfrac{1}{\underset{1}{\cancel{3}}}\times \dfrac{\overset{2}{\cancel{6}}}{5} \right)}\times \dfrac{5}{2}=\dfrac{\overset{1}{\cancel{2}}}{\underset{1}{\cancel{5}}}\times \frac{\overset{1}{\cancel{5}}}{\underset{1}{\cancel{2}}}=1 \\ \dfrac{1}{3}\times \textcolor{#2ab7ec}{\left(\dfrac{\overset{3}{\cancel{6}}}{\underset{1}{\cancel{5}} }\times \dfrac{\overset{1}{\cancel{5}}}{\underset{1}{\cancel{2}}} \right)}=\dfrac{1}{\underset{1}{\cancel{3}}}\times \overset{1}{\cancel{3}}=1 \\ \dfrac{1}{\underset{1}{\cancel{3}}}\times \dfrac{\overset{\overset{1}{\cancel{2}}}{\cancel{6}}}{\overset{1}{\cancel{5}}}\times \dfrac{\overset{1}{\cancel{5}}}{\underset{1}{\cancel{2}}}=1 \end{aligned}\end{rcases} \textcolor{#2ab7ec}{\left(\frac{1}{3}\times \dfrac{6}{5} \right)}\times \dfrac{5}{2}=\dfrac{1}{3}\times \textcolor{#2ab7ec}{\left(\dfrac{6}{5}\times \dfrac{5}{2} \right)}=\dfrac{1}{3}\times \dfrac{6}{5}\times \dfrac{5}{2}}
- Multiplication of sums and differences can be done by multiplying the terms separately and then adding or subtracting them.
\latex{\begin{rcases}\begin{aligned} \dfrac{2}{5}\times \left(\dfrac{10}{3}+\dfrac{5}{6} \right)=\dfrac{2}{5}\times \left(\dfrac{20}{6}+\dfrac{5}{6} \right)=\dfrac{\overset{1}{\cancel{2}}}{\underset{1}{\cancel{5}}} \times \dfrac{\overset{5}{\cancel{25}}}{\underset{3}{\cancel{6}}}&=\dfrac{5}{3} \\ \dfrac{2}{5}\times \dfrac{10}{3}+\dfrac{2}{5}\times \dfrac{5}{6}=\dfrac{\overset{2}{\cancel{10}}}{3}\times \dfrac{2}{\underset{1}{\cancel{5}}}+\dfrac{\overset{1}{\cancel{5}}}{\underset{3}{\cancel{6}}}\times \dfrac{\overset{1}{\cancel{2}}}{\underset{1}{\cancel{5}}}=\dfrac{4}{3}+\dfrac{1}{3}&=\dfrac{5}{3} \end{aligned}\end{rcases}}
Note:
Sums and differences can be divided by a fraction by multiplying them with the reciprocal of the fraction.

Exercises
{{exercise_number}}. Complete the operations
- \latex{ 8\times \left(\frac{1}{4}+\frac{1}{2}+\frac{5}{8} \right) };
- \latex{ \left(\frac{3}{32}+\frac{1}{80}+\frac{1}{50} \right)\times 16 };
- \latex{ \left(\frac{9}{10}-\frac{7}{30} \right)\times 10 };
- \latex{ \frac{2}{3} \times \left(\frac{3}{8}-\frac{3}{16} \right) };
- \latex{ \left(\frac{20}{9}-\frac{16}{15} \right)\times \frac{3}{4} };
- \latex{ \frac{27}{32}\times \left(\frac{5}{9}+\frac{1}{3} \right) }.
{{exercise_number}}. Are the results of the series of operations equal \latex{ (=) }, or not equal\latex{ (\neq ) }? Write the correct symbol in the square. Check your answers by calculating.
- \latex{ 5\times \frac{3}{11}+6\times \frac{3}{11} } \latex{\fcolorbox{black}{eaf1fa}{\phantom{--}}} \latex{ \left(5+6\right)\times \frac{3}{11} }
- \latex{ 3\times \frac{3}{8}+\frac{1}{8}\times 3 } \latex{\fcolorbox{black}{eaf1fa}{\phantom{--}}} \latex{ \left(3+\frac{1}{8} \right)\times 3 }
- \latex{ \frac{7}{8}\times 19-7\times \frac{7}{8} } \latex{\fcolorbox{black}{eaf1fa}{\phantom{--}}} \latex{ \frac{7}{8} \times \left(19-7\right) }
- \latex{ \frac{7}{10}\times 5-\frac{7}{10}\times \frac{5}{14} } \latex{\fcolorbox{black}{eaf1fa}{\phantom{--}}} \latex{ \left(5-\frac{5}{14} \right)\times \frac{7}{10} }
- \latex{ \frac{5}{4} \times 4+\frac{4}{5}\times \frac{5}{4} } \latex{\fcolorbox{black}{eaf1fa}{\phantom{--}}} \latex{ \frac{4}{5}\times \left(\frac{5}{4}+4 \right) }
- \latex{ \left(2\frac{1}{2}-\frac{16}{5} \right)\times \frac{5}{11} } \latex{\fcolorbox{black}{eaf1fa}{\phantom{--}}} \latex{ 2\frac{1}{2}\times \frac{5}{11}-\frac{16}{5}\times \frac{5}{11} }
{{exercise_number}}. Arrange the results of the following operations in ascending order.
- \latex{\frac{3}{4}-\left(\frac{7}{6}-\frac{1}{2} \right) }
- \latex{\frac{3}{5}\div \left(\frac{1}{2}-\frac{1}{3} \right) }
- \latex{ \left(\frac{2}{3}-\frac{2}{5} \right)\times \frac{1}{2} }
- \latex{ \frac{7}{2}\times \left(\frac{6}{5}\div \frac{1}{2} \right)}
- \latex{\frac{1}{3}+\frac{1}{5}-\frac{1}{30} }
- \latex{\frac{8}{5}\div \frac{1}{2}\times \frac{1}{4} }
{{exercise_number}}. Rewrite the operations as the multiplication or division of a sum or a difference. Check your answer by calculating. Which is the simpler procedure in each case?
For example: \latex{\frac{2}{3}\times \frac{4}{5}+\frac{2}{3}\times \frac{1}{5}=\frac{2}{3}\times \left(\frac{4}{5}+\frac{1}{5} \right)}
- \latex{\frac{8}{9}\times \frac{3}{8}+\frac{8}{9}\times \frac{2}{8}}
- \latex{\frac{5}{2}\times \frac{2}{5}-\frac{5}{2}\times \frac{1}{10}}
- \latex{5\frac{7}{20}\times 20}
- \latex{\frac{14}{3}\div 2-\frac{8}{5}\div 2}
- \latex{\frac{7}{2}\div 11+\frac{6}{5}\div 11}
- \latex{\frac{1}{2}\div 1\frac{1}{2}+\frac{7}{8}\div 1\frac{1}{2}}
{{exercise_number}}. At a bakery, the flour needed to make \latex{ 22 } loaves of bread has been taken out of a \latex{ 25\;kg } bag.
How much flour is left in the bag if \latex{\frac{3}{4}\;kg} of flour is needed to bake one loaf of bread?

{{exercise_number}}. Sixth-grade students wore ribbons as part of their Halloween costumes. The girls wore an \latex{ 80 \;cm } long pink ribbon, while the boys had a half-\latex{ metre }-long blue ribbon. How many boys and girls are in the sixth grade if \latex{ 15.5\; metres } of ribbon were used in total?
{{exercise_number}}. Edith is knitting a scarf. She completes \latex{ 1\frac{3}{5}\ m} every \latex{ hour. } How many \latex{ metres } does the length of the scarf increase in \latex{ 6 } \latex{ days } if she knits for half an \latex{ hour } each \latex{ day? } Which of the following operations expresses the solution of the exercise?
- \latex{ \left(1\frac{3}{5}\times \frac{1}{2} \right)\times 6 }
- \latex{ 1\frac{3}{5}\div \frac{1}{2} \times 6 }
- \latex{ \left(1\frac{3}{5}\times 6 \right)\div 2 }
- \latex{ 1\frac{3}{5}\div \left(2\times 6\right) }
- \latex{ 1\frac{3}{5}\times \frac{1}{2}\times 6 }
- \latex{ \left(1\frac{3}{5}\div 2 \right)\times 6 }
{{exercise_number}}. Write a word problem whose solution is
- \latex{8-\left(3+2\frac{1}{2} \right);}
- \latex{8-\left(3+2\frac{1}{2} \right);}
- \latex{\left(\frac{4}{5}+\frac{1}{2} \right)\times 2\frac{1}{2};}
- \latex{\frac{4}{5}\times 2\frac{1}{2}+\frac{1}{2}} .
Quiz
Organise the cards to make the equality true.
\latex{ 2 }
\latex{ 3 }
\latex{ 4 }
\latex{ 5 }
\latex{ + }
\latex{ \div }
\latex{ = }

