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The relation between the sides and the angles of the triangle
A triangle can clearly be defined by 
  1. its three sides;
  2. two of its sides and the included angle;
  3. one of its sides and the two angles on it;
  4. two of its sides and the angle opposite the longer side.
We are going to use this knowledge henceforth.
\latex{ \beta}
\latex{ \gamma}
Figure 32
\latex{ B }
\latex{ F }
\latex{ C }
\latex{ A }
Let us consider an isosceles triangle, and let point F be the mid-point of base BC (Figure 32). The corresponding sides of triangles ABF and AFC are equal in length, thus based on (1) \latex{\angle}ABF = \latex{\angle}FCA, which means that the angles on the base of triangle ABC are equal in size.
So we can say the following:
THEOREM: In a triangle there are equal angles opposite equal sides.
Using the notation of Figure 32:
\latex{AC = AB \Rightarrow \beta = \gamma}
From this theorem all interior angles of a equilateral triangle are \latex{60^{\circ}}.
It can be proven that the converse of the previous theorem is also true.
THEOREM: If two angles of a triangle are equal, then the sides opposite them are also equal.
Using the notation of Figure 32:
\latex{\beta = \gamma \Rightarrow AC = AB}

Let us assume that in triangle \latex{ ABC\, AC\gt AB }.

What can we say about the interior angles opposite sides \latex{ AC } and \latex{ AB ?}

Let point \latex{ D } be the point of side \latex{ AC } for which \latex{ AB = AD } (Figure 33). Then in triangle \latex{ ABD\, AB = AD }, from which \latex{\angle ABD= \angle BDA = \beta _{1}}.

Based on the theorem about the exterior angles of a triangle,
 
\latex{\beta = \beta _{1} +\beta _{2} \gt \beta _{1} = \beta _{2} + \gamma \gt \gamma }.
As a result if \latex{ AC\gt AB }, then \latex{\beta} > \latex{\gamma}. With this we have proven the following:
\latex{ \beta_{2}}
\latex{ \gamma}
\latex{ \beta_{1}}
\latex{ \beta_{1}}
Figure 33
\latex{ B }
\latex{ D }
\latex{ C }
\latex{ A }
THEOREM: If one side of a triangle is longer than another side, then the angle opposite the longer side will be larger than the angle opposite the shorter side. 
\latex{AC \gt AB \Rightarrow \beta \gt \gamma}
It can similarly be proven that the converse of this theorem is also true:
THEOREM:  In any triangle, the side opposite the larger interior angle is longer than the side opposite the smaller interior angle. 
\latex{\beta \gt \gamma \Rightarrow AC \gt AB}
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